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### Arithmetic Homework

Posted: Sun Aug 16, 2015 10:12 pm
Hello,

Once again, I stumbled onto another problem

42. Roses can be purchased individually for \$4.30, one dozen for \$36, or two dozen for \$50. What is the greatest number of roses that can be purchased for \$680?

(A) 156

(B) 162

(C) 318

(D) 324

(E) 325

### Re: Arithmetic Homework

Posted: Mon Aug 17, 2015 10:13 pm
325

### Re: Arithmetic Homework

Posted: Tue Aug 18, 2015 4:52 pm
Thank you but, I was hoping for a detailed solution.

- Thanks.

### Re: Arithmetic Homework

Posted: Wed Aug 19, 2015 8:35 am
Hi foguniy,

Nice to hear from you and glad that you are working hard on the GMAT.
You will certainly get a detailed explanation to the arithmetic problem above by GMAT experts as soon as possible.

Best regards,

### Re: Arithmetic Homework

Posted: Fri Aug 21, 2015 3:59 am
Hello fogundiy,

Below is the answer to the problem with an explanation from our senior
Manhattan Review instructor, George:

Answer to Question 42 is (E):

First figure out which are the cheapest roses. The first bunch is \$4.30
per rose, the second is \$3 per rose, the third is \$50/12 per rose. The
third is obviously the cheapest.

Clearly, to purchase the maximum number of roses, almost all of the
roses will have to be of the cheapest sort. How many can you purchase
for \$680? Divide 680 by 25/12. That comes to 326.4. Look among the
answer choices. How much will 324 of the cheapest cost? The answer is
\$675. Therefore, we have \$5 left over. We can buy an additional rose.
There is only one answer that is greater than 324, and that's (E), which
is 325.

We hope this explanation helps! To receive a free online practice exam
with similar challenging questions call us at +1.800.246.4600