by **Manhattan Review** » Fri Aug 21, 2015 4:02 am

Hello fogundiy,

Below is the answer to the problem with an explanation from our senior

Manhattan Review instructor, George:

Answer to Question 38 is (D):

Draw a pipe of length of 1 yard. You have to mark it out in 1/4s and

1/3s. Express that in terms of a common denominator, namely, 12. Thus,

1/4 is 3/12 and 1/3 is 4/12.

Start marking out the pipe. The first marker is 3/12, the second is

4/12, the third is 6/12, the fourth is 8/12, the fifth is 9/12, the

sixth is 12/12. Start cutting the pipe at each of the markers. The first

portion will be 3/12 or 1/4. The second portion will be 4/12 minus the

3/12 that has already been cut off, i.e., 1/12. The third portion will

be 6/12 minus the 4/12 that has already been cut off, i.e., 2/12 or 1/6.

The fourth will be 8/12 minus 6/12, i.e., 2/12 or 1/6. The fifth

will be 9/12 minus 8/12, i.e. 1/12. The sixth will be 12/12 minus 9/12,

i.e. 3/12 or 1/4.

There are thus only three distinct pipe lengths: 1/4, 1/6 and 1/12.

Answer (D).

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