by **Rafael_examPAL** » Thu Jun 29, 2017 10:31 am

We can use LOGIC to solve this question to be faster than using precise calculations.

a is negative.

Therefore a^2 is positive (a negative times a negative is positive)

and a^3 is negative.

but a is a fraction, therefore a^n is closer to 0 then a is. so a < a^3 (since a is negative)

i.e. a< a^3 < a^2

(B)